Difference between revisions of "2003 AMC 12A Problems/Problem 23"
Fuzzy growl (talk | contribs) (Created page with '== Solution == Using logarithmic rules, we see that <cmath>\log_{a}a-\log_{a}b+\log_{b}b-\log_{b}a = 2-(\log_{a}b+\log_{b}a</cmath> <math>=2-(\log_{a}b+\frac {1}{\log_{a}b}</ma…') |
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Revision as of 18:32, 22 February 2010
Solution
Using logarithmic rules, we see that
ab2-2=\boxed{0}.$