Difference between revisions of "2003 AMC 12B Problems/Problem 8"

(Created page with "Let <math>a</math> and <math>b</math> be the digits of <math>x</math>, <cmath>\clubsuit(x) = a + b = 3</cmath> Clearly the only two digit numbers whose digits sum to <math>3</m...")
 
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<cmath>\clubsuit(x) = a + b = 3</cmath>
 
<cmath>\clubsuit(x) = a + b = 3</cmath>
  
Clearly the only two digit numbers whose digits sum to <math>3</math> are <math>1, 2,</math> and <math>30.</math> Thus the solution is <math>3</math>. \Rightarrow {(A)}
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Clearly the only two digit numbers whose digits sum to <math>3</math> are <math>12, 21,</math> and <math>30.</math> Thus the solution is <math>3</math>. \Rightarrow {(A)}

Revision as of 20:39, 1 November 2012

Let $a$ and $b$ be the digits of $x$,

\[\clubsuit(x) = a + b = 3\]

Clearly the only two digit numbers whose digits sum to $3$ are $12, 21,$ and $30.$ Thus the solution is $3$. \Rightarrow {(A)}