Difference between revisions of "2004 AMC 10B Problems/Problem 5"
(New page: D =0; A must be determined either 3 or 2. 3^2 > 2^3, thus A is 3. B then follows to be 2 and C = 1. The result is 9, (D)) |
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Revision as of 02:50, 6 February 2009
D =0; A must be determined either 3 or 2. 3^2 > 2^3, thus A is 3. B then follows to be 2 and C = 1. The result is 9, (D)
