Difference between revisions of "2005 AMC 12B Problems/Problem 16"
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== Solution == | == Solution == | ||
| − | The eight spheres are formed by shifting spheres of radius <math>2</math> and center <math>(0, 0, 0)</math> <math>\pm 1</math> in the <math>x, y, z</math> directions. Hence, the centers of the spheres are <math>(\pm 1, \pm 1, \pm 1)</math>. | + | The eight spheres are formed by shifting spheres of radius <math>2</math> and center <math>(0, 0, 0)</math> <math>\pm 1</math> in the <math>x, y, z</math> directions. Hence, the centers of the spheres are <math>(\pm 1, \pm 1, \pm 1)</math>. For a sphere to contain all eight spheres, its radius must be greater than or equal to the longest distance from the origin to one of these spheres. This length is the intersection of one of the spheres and a line that goes through the origin and that sphere's center. This length is the sum of the distance from <math>(\pm 1, \pm 1, \pm 1)</math> to the origin and the radius of the sphere: |
== See also == | == See also == | ||
* [[2005 AMC 12B Problems]] | * [[2005 AMC 12B Problems]] | ||
Revision as of 19:25, 12 September 2010
Problem
Eight spheres of radius 1, one per octant, are each tangent to the coordinate planes. What is the radius of the smallest sphere, centered at the origin, that contains these eight spheres?
Solution
The eight spheres are formed by shifting spheres of radius 
and center 
in the 
directions. Hence, the centers of the spheres are 
. For a sphere to contain all eight spheres, its radius must be greater than or equal to the longest distance from the origin to one of these spheres. This length is the intersection of one of the spheres and a line that goes through the origin and that sphere's center. This length is the sum of the distance from to the origin and the radius of the sphere:
