Difference between revisions of "2006 AMC 10A Problems/Problem 7"

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== Problem ==
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#redirect [[2006 AMC 12A Problems/Problem 6]]
Missing diagram
 
 
 
The <math>8x18</math> rectangle <math>ABCD</math> is cut into two congruent hexagons, as shown, in such a way that the two hexagons can be repositioned without overlap to form a square.  What is <math>y</math>?
 
 
 
<math> \mathrm{(A) \ } 6\qquad \mathrm{(B) \ } 7\qquad \mathrm{(C) \ } 8\qquad \mathrm{(D) \ } 9\qquad \mathrm{(E) \ } 10 </math>
 
 
 
== Solution ==
 
Since the two hexagons are going to be repositioned to form a square without overlap, the area will remain the same. The rectangle's area is 18*8=144. This means the square will have four sides of length 12. The only way to do this is shown below.
 
[[Image:Square.jpg]]
 
 
 
== See Also ==
 
*[[2006 AMC 10A Problems]]
 

Latest revision as of 22:38, 27 April 2008

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