# Difference between revisions of "2006 AMC 12A Problems/Problem 13"

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== Problem == | == Problem == | ||

− | + | [[Image:2006 AMC 12A Problem 13.gif]] | |

The vertices of a <math>3-4-5</math> right triangle are the centers of three mutually externally tangent circles, as shown. What is the sum of the areas of the three circles? | The vertices of a <math>3-4-5</math> right triangle are the centers of three mutually externally tangent circles, as shown. What is the sum of the areas of the three circles? | ||

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{{solution}} | {{solution}} | ||

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+ | <math>\rm{(E)}\,14\pi</math> | ||

== See also == | == See also == | ||

* [[2006 AMC 12A Problems]] | * [[2006 AMC 12A Problems]] |

## Revision as of 02:58, 1 November 2006

## Problem

The vertices of a right triangle are the centers of three mutually externally tangent circles, as shown. What is the sum of the areas of the three circles?

## Solution

*This problem needs a solution. If you have a solution for it, please help us out by adding it.*