Difference between revisions of "2006 AMC 12A Problems/Problem 13"
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== Problem == | == Problem == | ||
| − | + | [[Image:2006 AMC 12A Problem 13.gif]] | |
The vertices of a <math>3-4-5</math> right triangle are the centers of three mutually externally tangent circles, as shown. What is the sum of the areas of the three circles? | The vertices of a <math>3-4-5</math> right triangle are the centers of three mutually externally tangent circles, as shown. What is the sum of the areas of the three circles? | ||
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{{solution}} | {{solution}} | ||
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| + | <math>\rm{(E)}\,14\pi</math> | ||
== See also == | == See also == | ||
* [[2006 AMC 12A Problems]] | * [[2006 AMC 12A Problems]] | ||
Revision as of 02:58, 1 November 2006
Problem
The vertices of a 
right triangle are the centers of three mutually externally tangent circles, as shown. What is the sum of the areas of the three circles?
Solution
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