Difference between revisions of "2006 AMC 12A Problems/Problem 8"
(added category and link to previous and next problem) |
(→Solution) |
||
| Line 6: | Line 6: | ||
== Solution == | == Solution == | ||
| + | 1+2+3+4+5 = 15 | ||
| + | 4+5+6 = 15 | ||
| + | 7+8 = 15 | ||
| + | |||
| + | The correct answer is C | ||
== See also == | == See also == | ||
Revision as of 20:48, 30 January 2007
Problem
How many sets of two or more consecutive positive integers have a sum of 
?
Solution
1+2+3+4+5 = 15 4+5+6 = 15 7+8 = 15
The correct answer is C
