Difference between revisions of "2006 AMC 8 Problems/Problem 1"
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== Solution == | == Solution == | ||
− | The three prices round to <math> \textdollar 2 </math>, <math> \textdollar 5 </math>, and <math> \textdollar 10 </math>, which | + | The three prices round to <math> \textdollar 2 </math>, <math> \textdollar 5 </math>, and <math> \textdollar 10 </math>, which have a sum of <math> \boxed{\textbf{(D)}\ 17} </math>. |
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+ | We know that there will not be a rounding error, as the total amount rounded is clearly less than <math> \textdollar 0.50 </math>. | ||
==See Also== | ==See Also== | ||
{{AMC8 box|year=2006|before=First <br />Question|num-a=2}} | {{AMC8 box|year=2006|before=First <br />Question|num-a=2}} | ||
{{MAA Notice}} | {{MAA Notice}} |
Latest revision as of 13:14, 18 March 2020
Problem
Mindy made three purchases for dollars, dollars, and dollars. What was her total, to the nearest dollar?
Solution
The three prices round to , , and , which have a sum of .
We know that there will not be a rounding error, as the total amount rounded is clearly less than .
See Also
2006 AMC 8 (Problems • Answer Key • Resources) | ||
Preceded by First Question |
Followed by Problem 2 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AJHSME/AMC 8 Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.