Difference between revisions of "2006 AMC 8 Problems/Problem 24"
Brightknight (talk | contribs) (Created page with "CDCD = CD*101, so ABA = 101. Therefore, A = 1 and B = 0, so A+B=1+0=1.") |
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CDCD = CD*101, so ABA = 101. Therefore, A = 1 and B = 0, so A+B=1+0=1. | CDCD = CD*101, so ABA = 101. Therefore, A = 1 and B = 0, so A+B=1+0=1. | ||
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| + | {{AMC8 box|year=2006|n=II|num-b=23|num-a=25}} | ||
Revision as of 19:34, 29 April 2012
Solution
CDCD = CD*101, so ABA = 101. Therefore, A = 1 and B = 0, so A+B=1+0=1.
| 2006 AMC 8 (Problems • Answer Key • Resources) | ||
| Preceded by Problem 23 |
Followed by Problem 25 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AJHSME/AMC 8 Problems and Solutions | ||
