Difference between revisions of "2006 Alabama ARML TST Problems/Problem 11"

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==See also==
 
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{{ARML box|year=2006|state=Alabama|num-b=10|num-a=12}}
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[[Category:Intermediate Number Theory Problems]]
 
[[Category:Intermediate Number Theory Problems]]

Revision as of 12:13, 29 September 2008

Problem

The integer $5^{2006}$ has 1403 digits, and 1 is its first digit (farthest to the left). For how many integers $0\leq k \leq 2005$ does $5^k$ begin with the digit 1?

Solution

Now either $5^k$ starts with 1, or $5^{k+1}$ has one more digit than $5^k$. From $5^0$ to $5^{2005}$, we have 1401 changes, so those must not begin with the digit 1. $2006-1401=\boxed{605}$

See also

2006 Alabama ARML TST (Problems)
Preceded by:
Problem 10
Followed by:
Problem 12
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