Difference between revisions of "2006 Canadian MO Problems/Problem 1"

 
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Let <math>f(n,k)</math> be the number of ways distributing <math>k</math> candies to <math>n</math> children so that each child receives at most two candies. For example, <math>f(3,7)=0</math>, <math>f(3,6)=1</math>, and <math>f(3,4)=6</math>. Evaluate <math>f(2006,1)+f(2006,4)+f(2006,7)+\dots+f(2006,1003)</math>.
 
Let <math>f(n,k)</math> be the number of ways distributing <math>k</math> candies to <math>n</math> children so that each child receives at most two candies. For example, <math>f(3,7)=0</math>, <math>f(3,6)=1</math>, and <math>f(3,4)=6</math>. Evaluate <math>f(2006,1)+f(2006,4)+f(2006,7)+\dots+f(2006,1003)</math>.
 
==Solution==
 
==Solution==
 
 
{{solution}}
 
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==See also==
 
*[[2006 Canadian MO]]
 
*[[2006 Canadian MO]]
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{{CanadaMO box|year=2006|before=First question|num-a=2}}

Revision as of 19:56, 7 February 2007

Problem

Let $f(n,k)$ be the number of ways distributing $k$ candies to $n$ children so that each child receives at most two candies. For example, $f(3,7)=0$, $f(3,6)=1$, and $f(3,4)=6$. Evaluate $f(2006,1)+f(2006,4)+f(2006,7)+\dots+f(2006,1003)$.

Solution

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See also

2006 Canadian MO (Problems)
Preceded by
First question
1 2 3 4 5 Followed by
Problem 2