2007 AIME I Problems/Problem 1

Revision as of 20:23, 15 March 2007 by Azjps (talk | contribs) (Solution: solution)

Problem

How many positive perfect squares less than $10^6$ are multiples of $24$?

Solution

The prime factorization of $24$ is $2^3\cdot3$; thus each square must have 3 factors of $2$ and 1 factor of $3$. This means that the square is in the form $\displaystyle (12c)^2$, where c is a positive integer. There are $\left\lfloor \frac{1000}{12}\right\rfloor = 083$ solutions.

See also

2007 AIME I (ProblemsAnswer KeyResources)
Preceded by
First Question
Followed by
Problem 2
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15
All AIME Problems and Solutions