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2007 AMC 8 Problems/Problem 24

Revision as of 22:00, 11 October 2010 by Sendhil (talk | contribs) (Moved from main page to its appropriate place)
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The combination of digits that give multiples of 3 are (1,2,3) and (2,3,4). The number of ways to choose three digits out of four is 4. So, the probability is $\frac{1}{2}$.

Answer : C

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