Difference between revisions of "2008 AMC 12A Problems/Problem 10"
(New page: Doug can paint <math>\frac{1}{5}</math> of a room per hour. Dave can paint <math>\frac{1}{7}</math> of a room in an hour. The time that they spend working together is <math>t-1</math>. Si...) |
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Revision as of 22:30, 18 February 2008
Doug can paint 
of a room per hour. Dave can paint 
of a room in an hour. The time that they spend working together is 
.
Since rate multiplied by time gives output:
