Difference between revisions of "2008 AMC 8 Problems/Problem 10"

(Created page with "==Problem 10== The average age of the <math>6</math> people in Room A is <math>40</math>. The average age of the <math>4</math> people in Room B is <math>25</math>. If the two gr...")
 
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==Problem 10==
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==Problem==
 
The average age of the <math>6</math> people in Room A is <math>40</math>. The average age of the <math>4</math> people in Room B is <math>25</math>. If the two groups are combined, what is the average age of all the people?
 
The average age of the <math>6</math> people in Room A is <math>40</math>. The average age of the <math>4</math> people in Room B is <math>25</math>. If the two groups are combined, what is the average age of all the people?
  

Revision as of 13:04, 9 December 2012

Problem

The average age of the $6$ people in Room A is $40$. The average age of the $4$ people in Room B is $25$. If the two groups are combined, what is the average age of all the people?

$\textbf{(A)}\ 32.5 \qquad \textbf{(B)}\ 33 \qquad \textbf{(C)}\ 33.5 \qquad \textbf{(D)}\ 34\qquad \textbf{(E)}\ 35$

See Also

2008 AMC 8 (ProblemsAnswer KeyResources)
Preceded by
Problem 9
Followed by
Problem 11
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AJHSME/AMC 8 Problems and Solutions