Difference between revisions of "2008 AMC 8 Problems/Problem 16"
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==Solution== | ==Solution== | ||
| − | The volume is of seven unit cubes which is <math>7</math>. The surface area is the same for each of the protruding cubes which is | + | The volume is of seven unit cubes which is <math>7</math>. The surface area is the same for each of the protruding cubes which is 5*6=30 The ratio of the volume to the surface area is D |
==See Also== | ==See Also== | ||
{{AMC8 box|year=2008|num-b=15|num-a=17}} | {{AMC8 box|year=2008|num-b=15|num-a=17}} | ||
{{MAA Notice}} | {{MAA Notice}} | ||
Revision as of 17:30, 8 August 2021
Problem
A shape is created by joining seven unit cubes, as shown. What is the ratio of the volume in cubic units to the surface area in square units?
![[asy] import three; defaultpen(linewidth(0.8)); real r=0.5; currentprojection=orthographic(1,1/2,1/4); draw(unitcube, white, thick(), nolight); draw(shift(1,0,0)*unitcube, white, thick(), nolight); draw(shift(1,-1,0)*unitcube, white, thick(), nolight); draw(shift(1,0,-1)*unitcube, white, thick(), nolight); draw(shift(2,0,0)*unitcube, white, thick(), nolight); draw(shift(1,1,0)*unitcube, white, thick(), nolight); draw(shift(1,0,1)*unitcube, white, thick(), nolight);[/asy]](http://latex.artofproblemsolving.com/5/6/0/560b1370f7552768e471e84d48e042295acbc628.png)
Solution
The volume is of seven unit cubes which is 
. The surface area is the same for each of the protruding cubes which is 5*6=30 The ratio of the volume to the surface area is D
See Also
| 2008 AMC 8 (Problems • Answer Key • Resources) | ||
| Preceded by Problem 15 |
Followed by Problem 17 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AJHSME/AMC 8 Problems and Solutions | ||
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