Difference between revisions of "2008 AMC 8 Problems/Problem 7"
(Created page with "==Problem 7== If <math>\frac{3}{5}=\frac{M}{45}=\frac{60}{N}</math>, what is <math>M+N</math>? <math>\textbf{(A)}\ 27\qquad \textbf{(B)}\ 29 \qquad \textbf{(C)}\ 45 \qquad \text...") |
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| − | ==Problem | + | ==Problem== |
If <math>\frac{3}{5}=\frac{M}{45}=\frac{60}{N}</math>, what is <math>M+N</math>? | If <math>\frac{3}{5}=\frac{M}{45}=\frac{60}{N}</math>, what is <math>M+N</math>? | ||
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\textbf{(D)}\ 105\qquad | \textbf{(D)}\ 105\qquad | ||
\textbf{(E)}\ 127</math> | \textbf{(E)}\ 127</math> | ||
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| + | ==Solution== | ||
| + | Separate into two equations <math>\frac35 = \frac{M}{45}</math> and <math>\frac35 = \frac{60}{N}</math> and solve for the unknowns. <math>M=27</math> and <math>N=100</math>, therefore <math>M+N=\boxed{\textbf{(E)}\ 127}</math>. | ||
==See Also== | ==See Also== | ||
{{AMC8 box|year=2008|num-b=6|num-a=8}} | {{AMC8 box|year=2008|num-b=6|num-a=8}} | ||
| + | {{MAA Notice}} | ||
Revision as of 01:30, 5 July 2013
Problem
If 
, what is 
?
Solution
Separate into two equations 
and 
and solve for the unknowns. 
and 
, therefore 
.
See Also
| 2008 AMC 8 (Problems • Answer Key • Resources) | ||
| Preceded by Problem 6 |
Followed by Problem 8 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AJHSME/AMC 8 Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
