Difference between revisions of "2008 iTest Problems/Problem 7"

(Solution)
Line 3: Line 3:
  
 
==Solution==
 
==Solution==
 +
 +
First, we complete the square of the left side of the equation, giving us:
 +
 +
<math>(n+5)^2 < 1983</math>
 +
 +
The integers from <math>-49</math> to <math>39</math> satisfy this equation, so the answer is <math> 39- (-49)+1 = 89</math>
  
 
==See also==
 
==See also==

Revision as of 19:03, 25 February 2016

Problem

Find the number of integers $n$ for which $n^2 + 10n < 2008$.

Solution

First, we complete the square of the left side of the equation, giving us:

$(n+5)^2 < 1983$

The integers from $-49$ to $39$ satisfy this equation, so the answer is $39- (-49)+1 = 89$

See also