# Difference between revisions of "2009 AIME I Problems/Problem 4"

God of Math (talk | contribs) m (→Solution) |
Ewcikewqikd (talk | contribs) (→Solution) |
||

Line 8: | Line 8: | ||

One of the ways to solve this problem is to make this parallelogram a straight line. | One of the ways to solve this problem is to make this parallelogram a straight line. | ||

− | So the whole length of the line<math>( | + | So the whole length of the line<math>(APC)</math> is <math>1000+2009=3009units</math> |

− | And <math> | + | And <math>AP</math> will be <math>17 units</math> |

So the answer is <math>3009/17 = 177</math> | So the answer is <math>3009/17 = 177</math> |

## Revision as of 19:17, 20 March 2009

## Problem 4

In parallelogram , point is on so that and point is on so that . Let be the point of intersection of and . Find .

## Solution

One of the ways to solve this problem is to make this parallelogram a straight line.

So the whole length of the line is

And will be

So the answer is