# Difference between revisions of "2009 AIME I Problems/Problem 4"

Ewcikewqikd (talk | contribs) (New page: == Problem 4 == In parallelogram <math>ABCD</math>, point <math>M</math> is on <math>\overline{AB}</math> so that <math>\frac {AM}{AB} = \frac {17}{1000}</math> and point <math>N</math> is...) |
Ewcikewqikd (talk | contribs) (→Solution) |
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One of the way to solve this problem is to make this parallelogram a straight line. | One of the way to solve this problem is to make this parallelogram a straight line. | ||

+ | |||

So the whole length of the line<math>(AP)</math> is <math>1000+2009=3009units</math> | So the whole length of the line<math>(AP)</math> is <math>1000+2009=3009units</math> | ||

+ | |||

And <math>AC</math> will be <math>17 units</math> | And <math>AC</math> will be <math>17 units</math> | ||

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So the answer is <math>3009/17 = 177</math> | So the answer is <math>3009/17 = 177</math> |

## Revision as of 17:32, 20 March 2009

## Problem 4

In parallelogram , point is on so that and point is on so that . Let be the point of intersection of and . Find .

## Solution

One of the way to solve this problem is to make this parallelogram a straight line.

So the whole length of the line is

And will be

So the answer is