Difference between revisions of "2009 AMC 10A Problems/Problem 1"
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I like pie (talk | contribs) (Added solution) |
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− | == Problem | + | == Problem == |
− | One can holds <math>12</math> ounces of soda. What is the minimum number of cans needed to provide a gallon (128 ounces) of soda? | + | One can holds <math>12</math> ounces of soda. What is the minimum number of cans needed to provide a gallon (<math>128</math> ounces) of soda? |
− | <math> | + | <math>\mathrm{(A)}\ 7\qquad |
− | \mathrm{(A)}\ 7 | + | \mathrm{(B)}\ 8\qquad |
− | \qquad | + | \mathrm{(C)}\ 9\qquad |
− | \mathrm{(B)}\ 8 | + | \mathrm{(D)}\ 10\qquad |
− | \qquad | + | \mathrm{(E)}\ 11</math> |
− | \mathrm{(C)}\ 9 | + | |
− | \qquad | + | == Solution == |
− | \mathrm{(D)}\ 10 | + | <math>10</math> cans would hold <math>120</math> ounces, but <math>128>120</math>, so <math>11</math> cans are required. Thus, the answer is <math>\mathrm{(E)}</math>. |
− | \qquad | + | |
− | \mathrm{(E)}\ 11 | + | {{AMC10 box|year=2008|ab=A|before=First Question|num-a=2}} |
− | </math> |
Revision as of 14:46, 15 February 2009
Problem
One can holds ounces of soda. What is the minimum number of cans needed to provide a gallon ( ounces) of soda?
Solution
cans would hold ounces, but , so cans are required. Thus, the answer is .
2008 AMC 10A (Problems • Answer Key • Resources) | ||
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