# Difference between revisions of "2009 AMC 10A Problems/Problem 1"

## Problem

One can holds $12$ ounces of soda. What is the minimum number of cans needed to provide a gallon ($128$ ounces) of soda?

$\mathrm{(A)}\ 7\qquad \mathrm{(B)}\ 8\qquad \mathrm{(C)}\ 9\qquad \mathrm{(D)}\ 10\qquad \mathrm{(E)}\ 11$

## Solution

$10$ cans would hold $120$ ounces, but $128>120$, so $11$ cans are required. Thus, the answer is $\mathrm{(E)}$.

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