Difference between revisions of "2010 AMC 10B Problems/Problem 16"
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| + | Area of Circle = <math>&pi r^2 = &pi/3</math> | ||
| + | Area of Square = <math>1^2 = 1</math> | ||
| + | |||
| + | Therefore answer = (A) <math>&pi/3 - 1</math> | ||
Revision as of 02:47, 1 March 2011
Area of Circle = $&pi r^2 = &pi/3$ (Error compiling LaTeX. Unknown error_msg)
Area of Square = 
Therefore answer = (A) $&pi/3 - 1$ (Error compiling LaTeX. Unknown error_msg)
