# Difference between revisions of "2010 AMC 10B Problems/Problem 16"

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+ | Radius of circle = <math>\frac{\sqrt{3}}{3} = \frac{1}{\sqrt{3}} = 0.577</math> | ||

+ | Half the diagonal of the square = <math>\sqrt{.5^2 + .5^2} = \frac{\sqrt{2}}{2} = 0.707</math> | ||

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+ | Therefore the picture will look something like this: | ||

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+ | [[Image:squarecircle.png]] | ||

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+ | Then you proceed to find the 4 * (area of the sector - are of the triangle) to get answer (B) |