Art of Problem Solving

AoPS Online

2010 AMC 12A Problems/Problem 1

Revision as of 20:49, 12 February 2010 by AIME15 (talk | contribs) (→‎Solution)

(diff) ← Older revision | Latest revision (diff) | Newer revision → (diff)

Problem 1

What is $\left(20-\left(2010-201\right)\right)+\left(2010-\left(201-20\right)\right)$ ?

$\textbf{(A)}\ -4020 \qquad \textbf{(B)}\ 0 \qquad \textbf{(C)}\ 40 \qquad \textbf{(D)}\ 401 \qquad \textbf{(E)}\ 4020$

Solution

$20-2010+201+2010-201+20=20+20=40; \boxed{\textbf{(C)}}$ .

Retrieved from "https://artofproblemsolving.com/wiki/index.php?title=2010_AMC_12A_Problems/Problem_1&oldid=33437"

© 2024 AoPS Incorporated