2010 AMC 12A Problems/Problem 3

Revision as of 19:37, 12 February 2010 by Rpond (talk | contribs)

Problem 3

Rectangle $ABCD$, pictured below, shares $50\%$ of its area with square $EFGH$. Square $EFGH$ shares $20\%$ of its area with rectangle $ABCD$. What is $\frac{AB}{AD}$?

[asy] unitsize(1mm); defaultpen(linewidth(.8pt));  draw((0,0)--(0,25)--(25,25)--(25,0)--cycle); fill((0,20)--(0,15)--(25,15)--(25,20)--cycle,gray); draw((0,15)--(0,20)--(25,20)--(25,15)--cycle); draw((25,15)--(25,20)--(50,20)--(50,15)--cycle); [/asy]

$\textbf{(A)}\ 4 \qquad \textbf{(B)}\ 5 \qquad \textbf{(C)}\ 6 \qquad \textbf{(D)}\ 8 \qquad \textbf{(E)}\ 10$

Solution

Let $EF = FG = GF = HE = s$, let $AD = BC = h$, and let $AB = CD = x$.


$.2s^2 = hs$

$s = 5h$

$.5hx = hs$

$x = 2s = 10h$


$\frac{AB}{AD} = \frac{x}{h} = \boxed{10\ \textbf{(E)}}$