Difference between revisions of "2010 AMC 8 Problems/Problem 7"
(Created page with "We need: 4 Pennies, 1 Nickel, 2 Dimes, and 2 Quarters Making 10 coins so the answer is B.") |
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1 Nickel, | 1 Nickel, | ||
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| − | + | 3 Quarters | |
| − | + | <math>4+1+2+3 = \boxed{\textbf{(B) } 10}</math> | |
Revision as of 00:27, 4 November 2012
We need:
4 Pennies, 1 Nickel, 2 Dimes, and 3 Quarters
