Difference between revisions of "2011 AMC 10A Problems/Problem 13"
Thedrummer (talk | contribs) (Created page with '==Problem 13== How many even integers are there between 200 and 700 whose digits are all different and come from the set {1,2,5,7,8,9}? <math>\text{(A)}\,12 \qquad\text{(B)}\,20…') |
|||
| Line 3: | Line 3: | ||
<math>\text{(A)}\,12 \qquad\text{(B)}\,20 \qquad\text{(C)}\,72 \qquad\text{(D)}\,120 \qquad\text{(E)}\,200</math> | <math>\text{(A)}\,12 \qquad\text{(B)}\,20 \qquad\text{(C)}\,72 \qquad\text{(D)}\,120 \qquad\text{(E)}\,200</math> | ||
| + | |||
| + | == Solution == | ||
| + | |||
| + | We split up into cases of the hundreds digits being <math>2</math> or <math>5</math>. If the hundred digits is <math>2</math>, then the units digits must be <math>8</math> in order for the number to be even and then there are <math>4</math> remaining choices (<math>1,5,7,9</math>) for the tens digit, giving <math>1 \times 1 \times 4=4</math> possibilities. Similarly, there are <math>1 \times 2 \times 4=8</math> possibilities for the <math>5</math> case, giving a total of \boxed{12 \ \mathbf{(A)}} possibilities. | ||
Revision as of 15:08, 14 February 2011
Problem 13
How many even integers are there between 200 and 700 whose digits are all different and come from the set {1,2,5,7,8,9}?
Solution
We split up into cases of the hundreds digits being 
or 
. If the hundred digits is , then the units digits must be 
in order for the number to be even and then there are 
remaining choices (
) for the tens digit, giving 
possibilities. Similarly, there are 
possibilities for the case, giving a total of \boxed{12 \ \mathbf{(A)}} possibilities.
