Difference between revisions of "2011 PuMAC Problems/Algebra Problem A1"

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Find the sum of the coefficients of the polynomial <math>(63x-61)^4</math>.
 
Find the sum of the coefficients of the polynomial <math>(63x-61)^4</math>.
  
== Solution ==
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== Solution 1 ==
 
Note that in a polynomial <math>\sum^{n}_{i=0} a_ix^i</math>, <math>x=1</math> gives <math>\sum^{n}_{i=0} a_i</math>, which is the sum of the coefficients.  
 
Note that in a polynomial <math>\sum^{n}_{i=0} a_ix^i</math>, <math>x=1</math> gives <math>\sum^{n}_{i=0} a_i</math>, which is the sum of the coefficients.  
 
Therefore, the sum of the coefficients of <math>(63x-61)^4</math> is <math>(63-61)^4 = 2^4 = \boxed{16}</math>
 
Therefore, the sum of the coefficients of <math>(63x-61)^4</math> is <math>(63-61)^4 = 2^4 = \boxed{16}</math>
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== Solution 2 ==
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Expanding, we get <math>15752961x^4 - 61011468x^3 + 88611894x^2 - 57199212x + 13845841</math>. Summing the coefficients, we have <math>15752961 - 61011468 + 88611894 - 57199212 + 13845841 = \boxed{16}</math>

Latest revision as of 20:15, 6 August 2023

Problem

Find the sum of the coefficients of the polynomial $(63x-61)^4$.

Solution 1

Note that in a polynomial $\sum^{n}_{i=0} a_ix^i$, $x=1$ gives $\sum^{n}_{i=0} a_i$, which is the sum of the coefficients. Therefore, the sum of the coefficients of $(63x-61)^4$ is $(63-61)^4 = 2^4 = \boxed{16}$

Solution 2

Expanding, we get $15752961x^4 - 61011468x^3 + 88611894x^2 - 57199212x + 13845841$. Summing the coefficients, we have $15752961 - 61011468 + 88611894 - 57199212 + 13845841 = \boxed{16}$