Difference between revisions of "2012 AMC 10A Problems/Problem 5"

(Problem 5)
(Solution)
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== Solution ==
 
== Solution ==
  
Half of the 100 adult cats are female, so there are <math>\frac{100}{2}</math> = <math>50</math> female cats.  Half of those female adult cats have a litter of kittens, so there would be <math>\frac{50}{2}</math> = <math>25</math> litters.  Since the average number of kittens per litter is 4, this implies that there are <math>25 \times 4</math> = <math>100</math> kittens.  So the total number of cats and kittens would be <math>100 + 100</math> = <math>\textbf{(B)}\ 200 </math>.
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Half of the 100 adult cats are female, so there are <math>\frac{100}{2}</math> = <math>50</math> female cats.  Half of those female adult cats have a litter of kittens, so there would be <math>\frac{50}{2}</math> = <math>25</math> litters.  Since the average number of kittens per litter is 4, this implies that there are <math>25 \times 4</math> = <math>100</math> kittens.  So the total number of cats and kittens would be <math>100 + 100</math> = <math>\boxed{\textbf{(B)}\ 200}</math>

Revision as of 21:08, 8 February 2012

Problem 5

Last year 100 adult cats, half of whom were female, were brought into the Smallville Animal Shelter. Half of the adult female cats were accompanied by a litter of kittens. The average number of kittens per litter was 4. What was the total number of cats and kittens received by the shelter last year?

$\textbf{(A)}\ 150\qquad\textbf{(B)}\ 200\qquad\textbf{(C)}\ 250\qquad\textbf{(D)}\ 300\qquad\textbf{(E)}\ 400$

Solution

Half of the 100 adult cats are female, so there are $\frac{100}{2}$ = $50$ female cats. Half of those female adult cats have a litter of kittens, so there would be $\frac{50}{2}$ = $25$ litters. Since the average number of kittens per litter is 4, this implies that there are $25 \times 4$ = $100$ kittens. So the total number of cats and kittens would be $100 + 100$ = $\boxed{\textbf{(B)}\ 200}$