Difference between revisions of "2013 AMC 10A Problems/Problem 1"

(Solution)
(Video Solution)
 
(11 intermediate revisions by 6 users not shown)
Line 1: Line 1:
A taxi ride costs <math>1.50 plus </math>0.25 per mile traveled.  How much does a 5-mile taxi ride cost?
+
==Problem==
  
 +
A taxi ride costs <math> \$1.50</math> plus <math>\$0.25</math> per mile traveled.  How much does a <math>5</math>-mile taxi ride cost?
  
 +
<math> \textbf{(A)}\ 2.25 \qquad\textbf{(B)}\ 2.50  \qquad\textbf{(C)}\ 2.75 \qquad\textbf{(D)}\ 3.00 \qquad\textbf{(E)}\ 3.75 </math>
  
 +
==Solution==
  
 +
There are five miles which need to be traveled. The cost of these five miles is <math>(0.25\cdot5) = 1.25</math>.  Adding this to <math>1.50</math>, we get <math>\boxed{\textbf{(C) }2.75}</math>
  
 +
==Video Solution (CREATIVE THINKING)==
 +
https://youtu.be/4XDyloZUY48
  
 +
~Education, the Study of Everything
  
  
 +
==Video Solution==
 +
https://youtu.be/hIklCIgfxcg
  
 +
~savannahsolver
  
 +
==See Also==
  
==''' Solution''' ==
+
{{AMC10 box|year=2013|ab=A|before=First Problem|num-a=2}}
There are five miles needed to be traveled, and there is 1.50 needed to be paid in addition to .25 dollars per mile. So, .25*5 + 1.50= 1.25+1.50= 2.75<math>
+
{{MAA Notice}}
 
 
So, the answer is </math>2.75 (C)
 

Latest revision as of 13:11, 1 July 2023

Problem

A taxi ride costs $$1.50$ plus $$0.25$ per mile traveled. How much does a $5$-mile taxi ride cost?

$\textbf{(A)}\ 2.25 \qquad\textbf{(B)}\ 2.50  \qquad\textbf{(C)}\ 2.75 \qquad\textbf{(D)}\ 3.00 \qquad\textbf{(E)}\ 3.75$

Solution

There are five miles which need to be traveled. The cost of these five miles is $(0.25\cdot5) = 1.25$. Adding this to $1.50$, we get $\boxed{\textbf{(C) }2.75}$

Video Solution (CREATIVE THINKING)

https://youtu.be/4XDyloZUY48

~Education, the Study of Everything


Video Solution

https://youtu.be/hIklCIgfxcg

~savannahsolver

See Also

2013 AMC 10A (ProblemsAnswer KeyResources)
Preceded by
First Problem
Followed by
Problem 2
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AMC 10 Problems and Solutions

The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. AMC logo.png