Difference between revisions of "2013 AMC 10B Problems/Problem 17"

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(Redirected page to 2013 AMC 12B Problems/Problem 10)
 
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==Problem==
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#REDIRECT [[2013 AMC 12B Problems/Problem 10]]
Alex has <math>75</math> red tokens and <math>75</math> blue tokens. There is a booth where Alex can give two red tokens and recieve in return a silver token and a blue token, and another booth where Alex can give three blue tokens and recieve in return a silver token and a red token. Alex continues to exchange tokens until no more exchanges are possible. How many silver tokens will Alex have at the end?
 
 
 
<math>\textbf{(A)} 62 \qquad \textbf{(B)} 82 \qquad \textbf{(C)} 83 \qquad \textbf{(D)} 102 \qquad \textbf{(E)} 103</math>
 
 
 
==Solution==
 
 
 
We can approach this problem by assuming he goes to the red booth first. You start with <math>75 \text{R}</math> and <math>75 \text{B}</math> and at the end of the first booth, you will have <math>1 \text{R}</math> and <math>112 \text{B}</math> and <math>37 \text{S}</math>. We now move to the blue booth, and working through each booth until we have none left, we will end up with:<math>1 \text{R}</math>, <math>2 \text{B}</math> and <math>103 \text{S}</math>. So, the answer is <math>\boxed{\textbf{(E)}103}</math>
 
== See also ==
 
{{AMC10 box|year=2013|ab=B|num-b=16|num-a=18}}
 

Latest revision as of 12:12, 7 April 2013