Difference between revisions of "2013 AMC 12A Problems/Problem 2"

(Created page with "To score twice as many runs as their opponent, the softball team must have scored an even number. Therefore we can deduce that when they scored 1, 3, 5, 7, and 9 runs, they lost...")
(No difference)

Revision as of 21:43, 6 February 2013

To score twice as many runs as their opponent, the softball team must have scored an even number.

Therefore we can deduce that when they scored 1, 3, 5, 7, and 9 runs, they lost by one run, and when they scored 2, 4, 6, 8, and 10 runs, they scored twice as many runs as their opponent.

Therefore, the total runs by the opponent is (2+4+6+8+10)+(1+2+3+4+5), which is 45, or C