2013 AMC 12A Problems/Problem 2
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To score twice as many runs as their opponent, the softball team must have scored an even number.
Therefore we can deduce that when they scored 1, 3, 5, 7, and 9 runs, they lost by one run, and when they scored 2, 4, 6, 8, and 10 runs, they scored twice as many runs as their opponent.
Therefore, the total runs by the opponent is (2+4+6+8+10)+(1+2+3+4+5), which is 45, or C
