Difference between revisions of "2013 AMC 12A Problems/Problem 8"
Epicwisdom (talk | contribs) (Created page with "<math> x+\tfrac{2}{x}= y+\tfrac{2}{y} </math> Since <math>x\not=y</math>, we may assume that <math>x=\frac{2}{y}</math> and/or, equivalently, <math>y=\frac{2}{x}</math>. Cross ...") |
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Revision as of 22:26, 6 February 2013
Since , we may assume that and/or, equivalently, .
Cross multiply in either equation, giving us .