Difference between revisions of "2014 AMC 12A Problems/Problem 2"

Revision as of 18:48, 7 February 2014

Suppose $x$ is the price of an adult ticket. The price of a child ticket would be $\frac{x}{2}$ .

$5x + 4(x/2) = 7x &= 24.50$ (Error compiling LaTeX. Unknown error_msg)

$x &= 3.50$ (Error compiling LaTeX. Unknown error_msg)

Plug in for 8 adult tickets and 6 child tickets.

$8x + 6(x/2) = 8(3.50) + 3(3.50) = 38.50$

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 Suppose <math>x</math> is the price of an adult ticket. The price of a child ticket would be <math>\frac{x}{2}</math>.
-<math>5x + 4(x/2) = 7x = 24.50</math>
+<math>5x + 4(x/2) = 7x &= 24.50</math>
-                <math>x = 3.50</math>
+<math>x &= 3.50</math>
 Plug in for 8 adult tickets and 6 child tickets.
 <math>8x + 6(x/2) = 8(3.50) + 3(3.50) = 38.50</math>