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2014 AMC 12B Problems/Problem 1

Revision as of 16:30, 20 February 2014 by Jared429 (talk | contribs) (Created page with "She has <math>p</math> pennies and <math>n</math> nickels, where <math>n + p = 13</math>. If she had <math>n+1</math> nickels then <math>n+1 = p</math>, so <math>2n+ 1 = 13 </mat...")
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She has $p$ pennies and $n$ nickels, where $n + p = 13$. If she had $n+1$ nickels then $n+1 = p$, so $2n+ 1 = 13$ and $n=6$. So she has 6 nickels and 7 pennies, which clearly have a value of 37 cents $\boxed

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