# Difference between revisions of "2016 AMC 10A Problems/Problem 14"

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The amount of twos in our sum ranges from <math>0</math> to <math>1008</math>, with differences of <math>3</math> because <math>2 \cdot 3 = lcm(2, 3)</math>. | The amount of twos in our sum ranges from <math>0</math> to <math>1008</math>, with differences of <math>3</math> because <math>2 \cdot 3 = lcm(2, 3)</math>. | ||

− | The possible amount of twos is <math>\frac{1008 - 0}{2} + 1 \Rightarrow \boxed{\textbf{( | + | The possible amount of twos is <math>\frac{1008 - 0}{2} + 1 \Rightarrow \boxed{\textbf{(C)} 337}</math> |

## Revision as of 18:59, 3 February 2016

## Solution

The amount of twos in our sum ranges from to , with differences of because .

The possible amount of twos is