2016 AMC 10A Problems/Problem 14

Revision as of 18:57, 3 February 2016 by Warrenwangtennis (talk | contribs) (Solution)

Solution

The amount of twos in our sum ranges from $0$ to $1008$, with differences of $3$ because $2 \cdot 3 = lcm(2, 3)$.

The possible amount of twos is $\frac{1008 - 0}{2} + 1 \Rightarrow \boxed{\textbf{(B)} 337$ (Error compiling LaTeX. ! File ended while scanning use of \boxed.)

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