# Difference between revisions of "2016 AMC 12A Problems/Problem 12"

(→Solution) |
m (→Solution) |
||

Line 4: | Line 4: | ||

<math>\frac{6}{AE} = \frac{7}{8 - AE}</math> so <math>AE = \frac{48}{13}</math> | <math>\frac{6}{AE} = \frac{7}{8 - AE}</math> so <math>AE = \frac{48}{13}</math> | ||

− | Similarly, <math>CD = 4</math> | + | |

+ | Similarly, <math>CD = 4</math>. | ||

Now, we use mass points. Assign point <math>C</math> a mass of <math>1</math>. | Now, we use mass points. Assign point <math>C</math> a mass of <math>1</math>. |

## Revision as of 13:13, 4 February 2016

## Solution

By the angle bisector theorem,

so

Similarly, .

Now, we use mass points. Assign point a mass of .

, so

Similarly, will have a mass of

So