2016 OIM Problems/Problem 5

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Problem

The circles $\Gamma_1$ and $\Gamma_2$ intersect at two different points $A$ and $K$. The tangent common to $\Gamma_1$ and $\Gamma_2$ closest to 4K$touches$\Gamma_1$at$B$and$\Gamma_2$at$C$.   Let$P$be the foot of the perpendicular from$B$on$AC$, and$Q$the foot of the perpendicular from$C$on$AB$. If$E$and$F$are the symmetrical points of$K$with respect to the lines$PQ$and$BC$, prove that the points$A, E$and$F$ are collinear.

~translated into English by Tomas Diaz. ~orders@tomasdiaz.com

Solution

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See also

OIM Problems and Solutions