2018 AIME I Problems/Problem 1

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A three-dimensional rectangular box with dimensions $X$, $Y$, and $Z$ has faces whose surface areas are $1746$, $1746$, $1854$, $1854$, $9991$, and $9991$ square units. What is $X$ + $Y$ + $Z$?


Solution 1(Currently Only the Answer is present, someone must give the solution)

The answer is $\boxed{218}$.