Difference between revisions of "2018 UNM-PNM Statewide High School Mathematics Contest II Problems/Problem 4"
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== Solution== | == Solution== | ||
| + | Let any one side be x and other side be y. | ||
| + | Then one diagonal is [(y)^2-(x)^2]^(1/2) | ||
| + | let [(y)^2-(x)^2]^(1/2) be z. | ||
| + | So x*z=39*95^(1/2) | ||
| + | |||
| + | Here x = 13 satisfies with y = 32 | ||
| + | so Perimeter is 2(13+32)=90 | ||
| + | |||
| + | =="90"== | ||
== See also == | == See also == | ||
Revision as of 01:24, 8 August 2019
Contents
Problem
Suppose ABCD is a parallelogram with area 
square units and 
is a right angle. If the lengths of all the sides of ABCD are integers, what is the perimeter of ABCD?
Solution
Let any one side be x and other side be y.
Then one diagonal is [(y)^2-(x)^2]^(1/2)
let [(y)^2-(x)^2]^(1/2) be z. So x*z=39*95^(1/2)
Here x = 13 satisfies with y = 32 so Perimeter is 2(13+32)=90
"90"
See also
| 2018 UNM-PNM Contest II (Problems • Answer Key • Resources) | ||
| Preceded by Problem 3 |
Followed by Problem 5 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 | ||
| All UNM-PNM Problems and Solutions | ||
