Difference between revisions of "2019 Mock AMC 10B Problems/Problem 2"
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− | Simply choosing 3 of the boy scouts predetermines the other 3 boy scouts so we have <math>{6 \choose 3}= | + | Simply choosing 3 of the boy scouts predetermines the other 3 boy scouts so we have <math>{6 \choose 3}=20</math> |
+ | <cmath></cmath><math>\boxed{\bold{D}}</math> | ||
+ | <math>\bold{20}</math> |
Latest revision as of 18:05, 8 October 2022
Simply choosing 3 of the boy scouts predetermines the other 3 boy scouts so we have