Difference between revisions of "2019 Mock AMC 10B Problems/Problem 2"

Revision as of 18:04, 8 October 2022

Simply choosing 3 of the boy scouts predetermines the other 3 boy scouts so we have ${6 \choose 3}=20$ $\[\]$ $\boxed{\bold{C}}$ $\bold{20}$

@@ Line 1: / Line 1: @@
-Simply choosing 3 of the boy scouts predetermines the other 3 boy scouts so we have <math>{6 \choose 3}=15</math>
+Simply choosing 3 of the boy scouts predetermines the other 3 boy scouts so we have <math>{6 \choose 3}=20</math>
 <cmath></cmath><math>\boxed{\bold{C}}</math>
-<math>\bold{15}</math>
+<math>\bold{20}</math>