Difference between revisions of "2019 Mock AMC 10B Problems/Problem 3"

(Created page with "After trying each option we have <cmath></cmath>A) <math>3^(2018/3)</math> which isn't rational as 2018 is not divisible by 3 <cmath></cmath>B) <math>3^(2019/2)</math> which...")
 
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After trying each option we have  
 
After trying each option we have  
<cmath></cmath>A) <math>3^(2018/3)</math> which isn't rational as 2018 is not divisible by 3
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<cmath></cmath>A) <math>3^(2018/3)</math> which isn't rational as 2018 is not divisible by 3<math>
<cmath></cmath>B) <math>3^(2019/2)</math> which isn't rational as 2019 isn't divisible by 2
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<cmath></cmath>B) </math>3^(2019/2)<math> which isn't rational as 2019 isn't divisible by 2</math>
<cmath></cmath>C) <math>3^2+\sqrt{2}^2+6\sqrt{2}</math> which equals <math>11+6\sqrt{2}</math> which is irrational
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<cmath></cmath>C) <math>3^2+\sqrt{2}^2+6\sqrt{2}</math> which equals <math>11+6\sqrt{2}</math> which is irrational<math>
<cmath></cmath>D) <math>(2pi)^2</math> equals <math>4pi^2</math> which is irrational
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<cmath></cmath>D) </math>(2pi)^2<math> equals </math>4pi^2<math> which is irrational</math>
<cmath></cmath>E) <math>(3-\sqrt{2})(3+\sqrt{2})=9-2=7</math> which is rational
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<cmath></cmath>E) <math>(3-\sqrt{2})(3+\sqrt{2})=9-2=7</math> which is rational<math>
We have <math>\boxed{\bold{E}}</math> <math>(3-\sqrt{2})(3+\sqrt{2})</math>
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We have </math>\boxed{\bold{E}}<math> </math>(3-\sqrt{2})(3+\sqrt{2})$

Revision as of 00:36, 23 September 2019

After trying each option we have \[\]A) $3^(2018/3)$ which isn't rational as 2018 is not divisible by 3$<cmath></cmath>B)$3^(2019/2)$which isn't rational as 2019 isn't divisible by 2$ \[\]C) $3^2+\sqrt{2}^2+6\sqrt{2}$ which equals $11+6\sqrt{2}$ which is irrational$<cmath></cmath>D)$(2pi)^2$equals$4pi^2$which is irrational$ \[\]E) $(3-\sqrt{2})(3+\sqrt{2})=9-2=7$ which is rational$We have$\boxed{\bold{E}}$$ (Error compiling LaTeX. Unknown error_msg)(3-\sqrt{2})(3+\sqrt{2})$