Difference between revisions of "2021 AIME I Problems/Problem 3"
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==Solution== | ==Solution== | ||
| + | <math>9+8+7+6+5+5+4+3+2+1=\boxed{50}</math> | ||
==See also== | ==See also== | ||
{{AIME box|year=2021|n=I|num-b=2|num-a=4}} | {{AIME box|year=2021|n=I|num-b=2|num-a=4}} | ||
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| + | [[Category:Introductory Number Theory Problems]] | ||
{{MAA Notice}} | {{MAA Notice}} | ||
Revision as of 16:58, 11 March 2021
Problem
Find the number of positive integers less than 
that can be expressed as the difference of two integral powers of 
Solution
See also
| 2021 AIME I (Problems • Answer Key • Resources) | ||
| Preceded by Problem 2 |
Followed by Problem 4 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 | ||
| All AIME Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
