Difference between revisions of "2021 Fall AMC 10B Problems/Problem 5"

Latest revision as of 01:17, 24 November 2021

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-==Problem 5==
+#REDIRECT [[2021_Fall_AMC_12B_Problems/Problem_4]]
-Let <math>n=8^{2022}</math>. Which of the following is equal to <math>\frac{n}{4}?</math>
-<math>(\textbf{A})\: 4^{1010}\qquad(\textbf{B}) \: 2^{2022}\qquad(\textbf{C}) \: 8^{2018}\qquad(\textbf{D}) \: 4^{3031}\qquad(\textbf{E}) \: 4^{3032}</math>
-==Solution 1==
-We have <cmath>n=8^{2022}=  \left(8^\frac{2}{3}\right)^{2022}=4^{3033}.</cmath>
-Therefore, <cmath>\frac{n}4=\boxed{(\textbf{E})\:4^{3032}}.</cmath>
-~kingofpineapplz
-==See Also==
-{{AMC10 box|year=2021 Fall|ab=B|num-a=6|num-b=4}}
-{{MAA Notice}}