Difference between revisions of "2021 WSMO Speed Round Problems/Problem 2"
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When a square is rotated about one of its sides, then it forms a cylinder. Thus, the answer is <math>4^3\pi\cdot\frac{90}{360}=16\pi.</math> Thus, the answer is <math>\boxed{16}.</math> | When a square is rotated about one of its sides, then it forms a cylinder. Thus, the answer is <math>4^3\pi\cdot\frac{90}{360}=16\pi.</math> Thus, the answer is <math>\boxed{16}.</math> | ||
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Revision as of 10:19, 23 December 2021
Problem
A square with side length of 
units is rotated around one of its sides by 
. If the volume the square sweeps out can be expressed as 
, find 
.
Solution
When a square is rotated about one of its sides, then it forms a cylinder. Thus, the answer is 
Thus, the answer is 
~pinkpig
