Difference between revisions of "2022 SSMO Speed Round Problems/Problem 1"

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-Since the power of <math>0</math> to an integer is  always <math>0</math>, it
-follows that we want to find the last digit of
-\begin{align*}
-    &2^2 + 2^{20} + 2^{202} + 2^{2023} + \\
-    &3^2 + 3^{20} + 3^{202} + 3^{2023}
-\end{align*}
-Since the powers of <math>2</math> are <math>2, 4, 8, 16, 32</math>
-it follows that <math>2^n</math> and <math>2^{n+4}</math> have the same last
-digit for <math>n \ge 1</math>. Similarily, <math>3^n</math> and <math>3^{n+4}</math> have the same last digit. (This follows as <math>\varphi(10) = 4</math> too).
-The expression then has the same last digit as
-\[
-^2 + 2^{4} + 2^{2} + 2^{3} + 3^2 + 3^{4} + 3^{2} + 3^{3}
-\]
-which is just <math>8</math>.

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